Teq Interview Questions, Process, and Tips

Out of 10 persons, 4 are graduates; so, (10 – 4) = 6 are under-graduates.

If there is no restriction, any three can be chosen from the ten in (10C3) = 120 ways.

Now, if all three chosen are under-graduates; it can take place in (6C3) = 20 ways.

Therefore, the probability that there will be no graduate among the three chosen = (20 / 120) = (1 / 6).

Therefore, the probability that there will be at least one graduate among the three chosen = {1 – (1 / 6)} = (5 / 6) = 0.8333.

Son in law

The 3-digit number can be written as the sequence [n, 2n, 3n]
n = 1 → [1, 2, 3] → valid
n = 2 → [2, 4, 6] → valid
n = 3 → [3, 6, 9] → valid

n = 4 → [4, 8, 12] is not valid because this would lead to a 4-digit number
any value of n > 4 would also produce invalid answer

Answer: Three numbers: {123, 246, 369}

16 poles per min
48kmph=48000 meters per hr
=800 meters per min
800/50=16 poles per min

C.1175

length of train = 150 m

( C ) Crawl

b

brother

6 pairs of earrings. So 12 earrings.

The total has to be 26, so let’s say there’s 6 pairs of earrings and the number of pairs has to be 4 less than the number of rings. So that would make 10 rings. The 10 rings has to be 2 1/2 greater than the number of pins. So you would divide 10/2.5 = 4 Pins. That would equate to a total of 12 earrings, 10 rings, and 4 pins. A total of 26 pieces.

430
5x5x6 = 150 cube

150 – 20( corner cube) = 130 cube

130 x 3 (side remaining) = 390
20 x 2 (side remaining) = 40
total side remaining = 390 + 40 = 430

P’s one min work=1/18
Q’s one min work=1/24
P’s x min work+Q’s 12 min work = tank fully filled ( 1 )
x(1/18)+12(1/24)=1
x=9 min

the ratio of present age of x:y is 5:6
And,we have to find the present age of x.
so,the present age of X is definitely will be multiple of 5.
X=35
so,35 is the answer.

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Lipimishra2

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Let the no. of men (originally) be x.
x no. of men require 10 days.

if however there were 10 men less it will take 10 days more for the work to be finished. ——> means x-10 men require 10+10=20 days.

10x = 20 (x-10)
x = 2x -20 => x = 20.

10%=394;50%=1970;250%=9850;30%=1182;
250%+30%=9850+1182=11032

Maximum number of edges = 9. Start from one corner. Select any face including that corner. Complete a square (4 edges) around the face to reach at the starting corner point . Now, move to the opposite face through the edge joining them and passing through the starting point(1 edge). Now, complete the square of edges around this face(4 edges). Total = 4+1+4 = 9 edges

A