240 m
if initially the price was Re 1.the new price nw bcoms to b
0.7..
so ,if the price z 0.7 ,the increment required is 0.3
so % in crement= 0.3/0.7*100=42.87…
17 secs
assume the ratio 6:4 to be 60:40
boys taking lunch in canteen=60% of 60=36
Girls taking lunch in the canteen=40% of 40=16
Total boys and girls taking lunch in the canteen=52
Total students we assumed is 60+40=100
Therefore percentage of boys and girls taking lunch in the canteen=(52/100)*100=52%
The queen gave two rings to two daughter’s and she kept the
third ring in her jewel box and she presented the ring to
her third daughter along with that jewel box.
Suppose the lengthier arm of weighing pan is of x cm and other arm is y cm .Also let weight if each melon be m kg.
so applying equilibrium of torque principles ,we get
case 1:-
1x-8my=0
case 2:-
2mx-1y=0
using case 1 equation , we substitute value of x into case 2 equation;
16mmy-1y=0
(16mm-1)y=0
y is length of weighing arm and cannot be 0,
therefore ,
16mm-1 =0
16mm=1
mm=1/16
m= square root (1/16)
m=+-1/4
m is weight of melon and cant be negative.
Hence m, weight of one melon is 1/4 kg
NON
area is given by Area of Rectangle = Length of Rectangle*(sqrt((Diagonal of Rectangle^2)-(Length of Rectangle^2)))
so substituting we get area=4*(sqrt((25-16)))
area=4*(sqrt(9))
since area cannot be negative hence we take sqrt of 9 as 3 (as sqrt of 9 is 3 and -3 as well)
area=4*3=12m^2
time = distance / speed
speed = 36*(5/18) m/s=10m/s
distance = 100m
time=100/10s = 10sec
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ans: 40
6/3*12/3*15/3=40
w, l=2w , area of square =8^2 = 64
area of rectangle = l*b
so w*2w = 8*64
w=16
length = 32
( d ) Cannot be determined