- Sunway construction group berhad General Aptitude Interview Questions
- Sunway construction group berhad Trainee Interview Questions
- Sunway construction group berhad Personal Questions round Interview Questions
- Sunway construction group berhad HR Interview Questions
- Sunway construction group berhad Lead Interview Questions
if am standing on a ballconi so i see the people what they
are doing and how they are handling with the people and
what they are taking to each and everybody.
To determine how many consecutive zeros the product of S will end with, we need to find the highest power of 10 that divides the product. This is equivalent to finding the highest power of 5 that divides the product, since the number of factors of 2 will always be greater than the number of factors of 5.
The primes in S are {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}.
There are 24 primes in S, so the product of S is:
2 x 3 x 5 x 7 x 11 x 13 x 17 x 19 x 23 x 29 x 31 x 37 x 41 x 43 x 47 x 53 x 59 x 61 x 67 x 71 x 73 x 79 x 83 x 89 x 97
We need to find the highest power of 5 that divides this product. To do this, we count the number of factors of 5 in the prime factorization of each number in S.
5 appears once: 5
5 appears once: 25
5 appears once: 35
5 appears once: 55
5 appears once: 65
5 appears once: 85
So, there are six factors of 5 in the product of S. However, we also need to consider the powers of 5 that arise from the factors 25, 35, 55, and 65.
25 = 5 x 5 appears once: 25
35 = 5 x 7 appears once: 35
55 = 5 x 11 appears once: 55
65 = 5 x 13 appears once: 65
Each of these numbers contributes an additional factor of 5 to the product of S. Therefore, there are 6 + 4 = 10 factors of 5 in the product of S.
Since each factor of 5 corresponds to a factor of 10, we know that the product of S will end with 10 zeros. Therefore, the product of S will end with 10 consecutive zeros
P+C+M=80
P+C=70
Therefore M=10
Given , P+M=90
If M=10
P=80
540 liters
1506
Statements :
Some kings are queens. All queens are beautiful.
Conclusions :
I. All kings are beautiful.
II. All queens are kings.
Conclusion 1 follows
(1/2)*x*y
343 : 729 :: 125 : ?
7^3 : 9^3 :: 5^3:7^3
( d ) Root
16, 25, 36, 72, 144, 196, 225
72
Because it is not a square number
15/46=0.32
13.5
225