Ques:- You have two jars, 50 red marbles and 50 blue marbles. A jar will be picked at random, and then a marble will be picked from the jar. Placing all of the marbles in the jars, how can you maximize the chances of a red marble being picked? What are the exact odds of getting a red marble using your scheme?
Recent Answer : Added by Admin On 2020-05-17 12:01:41:
put 1 red marble in one jar and all the rest (99) in the
other.
This gives you 50% from the first jar (if they pick that
jar they will get red 100% of the time). For the other jar
the chances are 49/99 or 49.494949%. Divide that by 2 and
its 24.7474%. Total odds are 50% plus 24.7474% = 74.7474%
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Ques:- Evaluate the sum of all even integers between 99 and 301?
Recent Answer : Added by Jagadeesh On 2022-09-15 16:37:00:
Summation of 301 – summation of 99
=41550
Summation of n=((n*n+1)/2)
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A
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Recent Answer : Added by Bala On 2022-09-22 16:40:04:
Gain=(profit/c.p)*100
Gain =selling price-cost price =900-675
=225.
Gain=(225/675)*100.
=33.3%
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B. 1010024
C. 9124
D. None of these
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a
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Recent Answer : Added by Admin On 2020-05-17 12:04:34:
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Ques:- Five years ago, the total of the ages of a father and his son was 40 years. The ratio of their present ages is 4 : 1. What is the present age of the father?
A. 20 years
B. 30 years
C. 40 years
D. 50 years
Recent Answer : Added by kkrajj On 2022-03-09 16:26:57:
Let x be fathers present age and y be son present age.
5 yrs ago, the age of father and son be x-5 & y-5.
Then,
x-5+y-5=40
x+y-10=40
x+y=50
y=50-x ———–> (1)
ratio between father and son in present age
x:y=4:1
x/y=4/1
x=4y
Apply eq (1) ,
x=4(50-x)
x=200-4x
x+4x=200
5x=200
x=200/5
x=40,,
=> The present age of father is 40.
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A. 13
B. 15
C. 16
D. 25
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put 1 red marble in one jar and all the rest (99) in the
other.
This gives you 50% from the first jar (if they pick that
jar they will get red 100% of the time). For the other jar
the chances are 49/99 or 49.494949%. Divide that by 2 and
its 24.7474%. Total odds are 50% plus 24.7474% = 74.7474%