SinglePoint Interview Questions, Process, and Tips

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Answer:
11 days.

Step-by-step explanation:
In the question,

Time taken by Ramesh to finish a piece of work = 20 days

Time taken by Sushil to finish a work = 25 days

Time for which they worked together = 5 days

Sushil left after = 5 days

So,

One day work of Ramesh is,

One day work of Sushil is,

So,

Work done in 5 days is given by,

Therefore, Remaining work is given by,

Now, as the Sushil left the remaining work was done by Ramesh,

Time taken by Ramesh for the remaining work is,

Therefore, the remaining work will be completed in 11 days by Ramesh.

1) time =20mins,speed=15kmph=15*(5/18)=25/6 m/sec
distance=20*(25/6)=250/3 m
then 2) given as time =15min
speed=250/3*15=(50/9)*(18/5)kmph=20kmph

3*2-1=5
5*2-2=8
8*2-3=13
13*2-4=22
22*2-5=39
39*2-6=72
so series is 3,5,8,13,22,39,72
24 should be replaced by 22
24 is wrong…….

Ans is 2(Prime numbers)

Sum of 5 consecutive nos is 35

so X + (X+1) + (X+2) + (X+3)+ (X+4) = 35

5X + 10 = 35

X = 5

So the 5 consecutive numbers are : 5, 6, 7, 8, 9

The Prime numbers are 5 and 7

Yes, it is possible by using a HDMI cable

200/3

– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.

– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m

To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec

In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m

at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m

If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)

Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.

For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.

This will take an additional (9.6 + 2) seconds.

Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds

perimeter = pi(r) + 2r
= 19.782 + (12.6)
= 32.382 cm

Correct option is A)
2nd term =(1stterm×1+2)=(4×1+2)=6
3rd term =(2ndterm×2+3)=(6×2+3)=15
4th term =(3rdterm×3+4)=(15×3+4)=49
5th term =(4thterm×4+5)=(49×4+5)=201 and so on
∴5 is wrong.

A