Ques:- Anil invested a sum of money at a certain rate of simple interest for a period of five years. Had he invested the sum for a period of eight years for the same rate, the total intrest earned by him would have been sixty percent more than the earlier interest amount. Find the rate of interest p.a.
Ques:- 1) In a club there are certain no. of males and females. If 15 females are absent then no. of males will be twice that of females. If 45 males are absent then female strength will be 5 times that of males. Find no. of males actually present.
Ques:- 2 men are walking towards each other at constant speeds.A train starting at one end crosses the first man in 18 seconds. After 10 minutes it meets the other man and crosses him in 12 seconds.(i am not sure of the values).Find the time when the 2 …
Ques:- Find out the wrong number in a given series.
263, 284, 393, 481, 482
263, 284, 393, 481, 482
A. 482
B. 481
C. 393
D. 284
Recent Answer : :
B
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Recent Answer : :
A rude person who doesn’t respect me
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Ques:- In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class? (1) Data inadequate (2) 20 (3) 25 (4) 30 (5) None of these
Recent Answer : :
let no. of boys not participating be x
then the no. of girls not participating = x+5
no. of boys : girls participating = 3:2
given no.of boys participating = 15
therefore, the ratio is now 15:y(say)
then 3:2 = 15 : x
on solving 3/2 =15/y ie.., 3y =30 we get y =10
hence no. of girls participating =10
therefore total no of students paricipating = 15+10=25
total no of students in class =60 given
hence no. of students not participating = 60-25=35
therefore x+(x+5)=35
2x=30
x=15
therfore no of girls not participating =15+5=20
therefore total no of girls in class = no of girls
participating + no of girls not participating
=10+20
=30 is the answer
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A. 2.4 mph
B. 4 mph
C. 4.8 mph
D. 5 mph
E. None of above
Recent Answer : :
C. 4.8 mph
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Ques:- A train 240 m long passed a pole in 24 seconds. How long will it take to pass a platform 650 m long?
A. 65 sec
B. 79 sec
C. 89 sec
D. 99 sec
Recent Answer : :
240-24
650-?
?=24*650/240
65SEC
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Ques:- The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
Recent Answer : :
slower train – 48 kmph = 40/3 m/s
say faster train, v m/s
therefore, {v-(40/3)}*180 = 600, => v= 60 kmph
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Recent Answer : :
1000
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Recent Answer : :
156
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Recent Answer : :
Collective performance
Postive attitude towards working
Shaping team player
Turning individuals into team players
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Recent Answer : :
Chi-ca-go
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Ques:- X can do a piece of work in 40 days; Y can do the same in 30 days. X started alone but left the work after 10 days, then Y worked at it for 10 days. Z finished the remaining work in 10 days. Z alone can do the whole work in?
Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.