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• HCF = 2

• LCM = 70

Let the two numbers be 2a and 2b
(Since HCF is 2, both numbers must be divisible by 2)

So,
LCM of 2a and 2b = 2ab
And the product of the numbers = 2a × 2b = 4ab

Now,
We know:

Product of the two numbers = HCF × LCM
⇒ 4ab = 2 × 70 = 140
⇒ ab = 35

Now we need to find two numbers a and b such that:

• ab = 35

• and a, b are co-prime (because HCF of original numbers is already taken as 2)

Factors of 35 that are co-prime:
1 × 35, 5 × 7

Try a = 5, b = 7
⇒ Numbers = 2a = 10 and 2b = 14
Or vice versa: 14 and 10

—

✅ Final Answer: The two numbers are 10 and 14.

We are given:

• January 1, 1992 was a Wednesday

• We are to find the day on January 1, 1993

🧠 Step 1: Check if 1992 is a leap year

A year is a leap year if it is divisible by 4 and:

• Not divisible by 100

• Unless it is also divisible by 400

✅ 1992 is divisible by 4 ⇒ Yes, it is a leap year
So it has 366 days

🧮 Step 2: Count odd days

• 366 days = 52 weeks + 2 extra days (called odd days)
  → So, the weekday shifts forward by 2 days

📅 Step 3: Move 2 days forward from Wednesday

• Wednesday + 1 day = Thursday

• +1 more = Friday

✅ Final Answer:
January 1, 1993 was a Friday.