Rajiv Gandhi Institute of Technology (India) Interview Questions, Process, and Tips

1.5 km/hour

A can copy 50 papers in 10 hrs
that means 5 papers in 1 hour
A & B can copy 70 papers in 10 hrs
that means both of them copy 7 papers in 1hour
we know A can copy 5 papers
there fore B can copy 2papers in 1 hour
so B can copu 26 papers in x hours
2*x=26
x=26/2=13 hours

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B. 3 : 2

X= pigeon
Y= hares
X+Y= 200
2x+4y=580
By solving y= 90
X=110
So Hares= 90

the ratio is 4 : 3
so -> let’s suppose a case where multiplying both sides for the same number, the sum of the result will be 28 …

4 * 4 = 16
4 * 3 = 12
16 + 12 = 28

in 8 years they will be respectvely 24 and 20
which is the same as 6/5

obey

let x be the avg age of each person in the family ten years
back…
so total age=6x
after 10 years i.e,now the total age of the family =6x+60
let grand father age as y
then the average of the family=(6x+60-y)/5
(bcoz grand father has expired and the new born baby has no
age at present)
according to the given question (6x+60-y)/5=x
bcoz x is the avg age bfore 10 years.
while calc the equation according to the presnt age we have
to add 10 to the result….
so the answer is 70

answer 10

160600

Matches played: 60.
Matches won: 30% of 60 => (60*(30/100)) = 18 matches.
Iterative approach:
On adding 1 to matches played and matches won, on every iteration until the win percentage gets to 50. So
19 / 61 = 0.3114754098360656
20 / 62 = 0.3225806451612903
21 / 63 = 0.3333333333333333
22 / 64 = 0.34375
…
…
…
…
Similarly,
41 / 83 = 0.4939759036144578
42 / 84 = 0.5

So, after 60th match 24 more matches has to be played and won to get 50% average winning rate.

B. No such pair exists