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Ques:- A bus has 40 seats and the passengers agree to share the total bus fare among themselves equally. If the total fair is 80.67 , find the total no of the seats unoccupied.
Recent Answer : Added by Admin On 2020-05-17 12:02:21:
37 SEATS….
because if passengers will occupy 3 seats, per head amount
payable will be 26.89.80.67 can not be divisible other than
3 and 26.89. so the,
Number of occupied seats will be 3
Number of unoccupied seats will be 40-3=37
Ques:- What is the missing number in the series. 1, 4, 27, 256, ?, 46656
Recent Answer : Added by Deepikaa Nandakumar On 2022-05-17 09:08:52:
1^1,2^2,3^3,4:^4,5^5,6^6
1,4,27,256,3125,46656
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Ques:- How many litres of pure acid are there in 8 litres of a 20% solution?
A. 1.4
B. 1.5
C. 1.6
D. 2.4
Recent Answer : Added by Kasoja Shiva On 2022-03-09 16:26:30:
1.6
Ques:- Of Abdul, Binoy, and Chandini: a)Each member belongs to the Tee family whose members always tell the truth or to the El family whose members always lie. b)Abdul says ''Either I belong or Binoy belongs to a different family from the other two.” Whose family do you name of?
Ques:- A boy has Rs 2. He wins or loses Re 1 at a time If he wins he gets Re 1 and if he loses the game he loses Re 1. He can loose only 5 times. He is out of the game if he earns Rs 5. Find the number of ways in which this is possible?
Recent Answer : Added by Admin On 2022-09-28 17:58:34:
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NabasishGogoi
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0L -> 1 way
1L -> 3 ways
2L -> 7 ways
3L -> 4 ways
4L -> 1 way
total 16 ways
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Ques:- Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern?
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Recent Answer : Added by milan On 2021-08-09 17:01:35:
151
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Ques:- Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is -.
Recent Answer : Added by Admin On 2022-09-28 18:05:55:
Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1 cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2 i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61,P(B)=61,P(C)=65,P(A)=61,P(B)=65,P(C)=61 and P(A)=65,P(B)=61,P(C)=61
Hence the required probability = 61×61×65×6×3=21690=125
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37 SEATS….
because if passengers will occupy 3 seats, per head amount
payable will be 26.89.80.67 can not be divisible other than
3 and 26.89. so the,
Number of occupied seats will be 3
Number of unoccupied seats will be 40-3=37