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Recent Answer : :
(x+2)^2 -x^2 = 84
X=20
So (20,22)
Sum= 42
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1min = 60 seconds
6 min=6*60=360seconds
4 sec=10
360sec=360*10 /4=900
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North
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23 Teams
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A. 923872
B. 923972
C. 923862
D. 923962
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Recent Answer : :
Ans 635.5
4000
1 year 5 % 200 rs int
Total 4200
2 year 5 % 210 ra int
Total 4410
4410-2210 = 2200
1 year 5% 110
Total 2310
2 year 5 % 115.5 rs int
Total 2425.5
Total interest paid
200 +210+ 110+115.5. = 635.5
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Recent Answer : :
ans: 40
6/3*12/3*15/3=40
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Ques:- How many 3 digit numbers are those in between 100 and 300, having first and the last digit as 2?
A. 9
B. 10
C. 11
D. 12
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10
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35Kg
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$20
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Ques:- A man driving the car at twice the speed of auto oneday He was driven car for 10 min. And car is failed. He left The car and took auto to goto the office .He spent 30 min. In the auto. What will be the time take by car to go office?
A. 25
B. 30
C. 35
D. none
Recent Answer : :
this is a simple question but the questionaire needs us to
consume time.
speed of car = 2 * speed of auto.
auto takes 30 mins then car should take only 15 mins.
total time = 10 mins + 15 mins = 25 mins = (a)
Ques:- If + means * and * means / and / means %. what is the value of 2+3*5/7?
Recent Answer : :
wake up guys and see modulo % can return only integer value.
So answer will be 1 and all other answers are wrong. You can
run your equation in C code and check the output.
Given:
In a group of 15 students,
7 have studied Latin,
8 have studied Greek,
3 have not studied either.
To find:
The number of students who studied both Latin and Greek.
Solution:
In a group of 15 students, have studied Latin, 8 have studied Greek, 3 have not studied either.
Therefore,
n(A∪B) = 15 – 3
n(A∪B) = 12
7 have studied Latin,
n(A) = 7
8 have studied Greek,
n(B) = 8
n(A∩B) is the number of students who studied both Latin and Greek.
n(A∩B) = n(A) + n(B) – n(A∪B)
n(A∩B) = 7 + 8 – 12
n(A∩B) = 15 – 12
n(A∩B) = 3
The number of students who studied both Latin and Greek is 3
Final answer:
3 of them studied both Latin and Greek.
Thus, the correct answer .3