Iotap Interview Questions, Process, and Tips

211

Mm

38 years

Let Rajan’s present age be x years. Then, his age at the time of marriage = (x – 8) years.

x = 65(x−8)

⇒5x=6x−48

⇒x=48 years

Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = (x – 18) = 30 years

∴ Rajan’s sister’s present age = (30 + 8) years = 38 years

let the total no of breads be x.
1st man 2nd man
x- (x/2) – 1/2 – 1/2((x-1)/2) – 1/2 ….. so on.
ans is 31.
first ate : 15.5 + .5 = 16 remaining 15
second ate : 7.5+0.5 = 8 remaining 7.
third ate : 3.5 +0.5 = 4 remaining 3.
fourth ate : 1.5 + 0.5 = 2 remaining 1
fifth ate : 0.5 + 0.5 = 1 remaining 0

Cake is never cut in such a way.
Wat we can do is.
1st cut should be cutting the Cake into two Halfs
Now put one half on top of other. Then again cutting it like
we made the 1st cut.
so now 4 parts. Two on top two on below.
Now Cut the cake in the orthogonal direction than the
earlier two cuts.
The trick was only That u can put one half on top of other.
Tats it.

( d ) 6 days

Example 1:
Assign, A=20, B=10, C=5, D=5(Because C is equal to D as
given), E=1.
A/B = 20/10 = 2. So A/B = 2
A/C = 20/5 = 4. So A/C = 4
A/E = 20/1 = 20. So A/E = 20
Therefore “A/E is Greatest”
Example 2:
Assign, A=100, B=50, C=20, D=20(Because C is equal to D as
given), E=10.
A/B = 100/50 = 2. So A/B = 2
A/C = 100/20 = 5. So A/C = 5
A/E = 100/10 = 10. So A/E = 10
Therefore “A/E is Greatest”

12%

160600

40
40
30
60
– 10 cows
+ 20 days
if 40 cows can eat for forty days
then 20 cows can eat for 80 days

Ans is 2(Prime numbers)

Sum of 5 consecutive nos is 35

so X + (X+1) + (X+2) + (X+3)+ (X+4) = 35

5X + 10 = 35

X = 5

So the 5 consecutive numbers are : 5, 6, 7, 8, 9

The Prime numbers are 5 and 7

5/9

2 urns, 9 balls.
4(2)+1=9 and 3(2)+3=9
You can’t put 4 balls in each of 7 urns with balls left over when 7*4=28. 28>24.