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Ques:- A certain sum is invested at simple interest at 18% p.a. for two years instead of investing at 12% p.a. for the same time period. Therefore the interest received is more by Rs. 840. Find the sum?
Recent Answer : Added by Nikhil Ambigar On 2022-01-08 16:05:06:
let x be sum.
SI of 18% for 1 year= x*18/100=0.18x;
SI of 18% for 2 years is 0.36x;
SI of 12% for 1 year= x*12/100=0.12x;
SI of 12% for 2 years is 0.24x;
Given, 0.36x-0.24x=840
0.12x=840
x=840/0.12=7000.
Ques:- The ratio of the earnings of P and Q is 9:10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?
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Recent Answer : Added by Upendra Dwivedi On 2022-08-14 16:33:18:
6/5
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Ques:- In an examination, 80% of the students passed in English, 85% in Mathematics and 75% in both English and Mathematics. If 40 students failed in both the subjects the total number of students is
A. 200
B. 400
C. 600
D. 800
Recent Answer : Added by Phani On 2022-03-09 16:41:44:
Percentage of people passed = (passed in eng) + (passed in math) – ( passed in both)
Which is 90% of students passed and 10% failed
10% of X = 40
X = 400
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Recent Answer : Added by Mubeena kabeer On 2021-04-15 17:10:50:
A wet stone
Ques:- one man driving a car in a lonely forest .. it was raining at that moment …suddenly one of the car tyre got punchured…and he is having stephiny in his car …he gets it and he tried to fix that stephiny…when he removes the bolts of punchred tire all are gone into mud…all bolts… fell into mud…and that bolts he never get…then, how can he reach safely to home… by driving his car..?
Recent Answer : Added by Admin On 2020-05-17 12:03:16:
he removed one bolt in each three wheels
and fixed the bolts in stephiny wheel
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Recent Answer : Added by t On 2022-01-08 16:07:00:
6
Ques:- There is a 50m long army platoon marching ahead. The last person in the platoon wants to give a letter to the first person leading the platoon. So while the platoon is marching he runs ahead, reaches the first person and hands over the letter to him and without stopping he runs and comes back to his original position. In the mean time the whole platoon has moved ahead by 50m. The question is how much distance did the last person cover in that time. Assuming that he ran the whole distance with uniform speed.
Recent Answer : Added by Admin On 2020-05-17 12:00:37:
The last person covered 120.71 meters.
It is given that the platoon and the last person moved with
uniform speed. Also, they both moved for the identical
amount of time. Hence, the ratio of the distance they
covered – while person moving forward and backword – are
equal.
Let’s assume that when the last person reached the first
person, the platoon moved X meters forward.
Thus, while moving forward the last person moved (50+X)
meters whereas the platoon moved X meters.
Similarly, while moving back the last person moved [50-(50-
X)] X meters whereas the platoon moved (50-X) meters.
Now, as the ratios are equal,
(50+X)/X = X/(50-X)
(50+X)*(50-X) = X*X
Solving, X=35.355 meters
Thus, total distance covered by the last person
= (50+X) + X
= 2*X + 50
= 2*(35.355) + 50
= 120.71 meters
Note that at first glance, one might think that the total
distance covered by the last person is 100 meters, as he
ran the total lenght of the platoon (50 meters) twice.
TRUE, but that’s the relative distance covered by the last
person i.e. assuming that the platoon is stationary.
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Recent Answer : Added by DK BOSS On 2021-07-21 15:27:16:
i am looking for a cyber security expert job
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Recent Answer : Added by as On 2021-05-16 16:12:43:
brother and sister
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Recent Answer : Added by Hemant Verma On 2021-08-16 03:57:58:
Kisan Baburao Hazare
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Recent Answer : Added by dilshad On 2021-03-26 17:27:29:
Indira Gandhi
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A. a) If no. is odd it is head, if no. is even it is tail
B. b) vice versa...
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let x be sum.
SI of 18% for 1 year= x*18/100=0.18x;
SI of 18% for 2 years is 0.36x;
SI of 12% for 1 year= x*12/100=0.12x;
SI of 12% for 2 years is 0.24x;
Given, 0.36x-0.24x=840
0.12x=840
x=840/0.12=7000.