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A. 15
B. 30
C. 40
D. 45
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Ques:- Find the smallest number which when divided by 13 and 16 leaves respective remainders of 2 and 5.
Recent Answer : :
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= (208) – (11) = 197.
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Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45