31
0,8x= y
y – 0,7y = 270
y= 270 / 0,3
y=900
0,8x=900
x=1125
In the example first we have to find the area of the field
we have given the following values ,
cost of fencing per meter = Rs 1.50
Diameter of circular field = 28
We have to find the area , a = ?
We know that,
Area = 2 π r
= 2 x 22/7 x 14
= 2 x 22 x 2
= 44 x 2
= 88 sq. m
So, area of circle is 88 sq.m
Now just multiply it with 1.50
cost of fencing = 88 x 1.50
= Rs. 132
So, the cost of fencing the circular field is Rs. 132
Second
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as i assume the time taken to complete the job is not to be
changed while increasing the employees as it does not
clearly states so……….
30 men wrk for 9 hrs
therefore for the work to be done if no of workers is
increases the no of hrs / day to work should decrease so
here s a inverse relation
solving further we get
30 = K /9 ==> K= 270
now
40 = 270/y ==> y= 6.75
therefore ans is d)none
If discount is 25%
Profit 25%
If discount10%
Profit?
Suppose 100rs is price
25% discount make it 75
25%profit that means 75×100/125=60
Cp is 60
10 % discount make sp 90 profit is 30%
( a ) 11
c
Let the money borrowed by Nitin=Rs.P
According to the question,
(P×6×3)/100+(P×9×5)/100+(P×13×3)/100=Rs.8160
ans=8000
X-Y=-1
I think speed of printing per minute has nothing do to with how long printer being at work.
If “given day” = 8 hours.
8h = 480m
x = 176400 / 480 = 367.5 lines per minute.