Hpe software Interview Questions, Process, and Tips

Fathers before age=3*before sons age—-(1)
After 2.5 years..
Fathers before age+2.5 years =2.5*sons age—-(2)
Substitute (1) in (2),
3*sons before age+2.5 years=2.5*sons age
0.5*sons age=2.5 years
Sons before age=5years
So current age after 2.5 years,
Sons before age+2.5 =5+2.5=7.5 years

choosing my career path

C will get RS 95

x:y=18:11

ans is C.
let H be present age of husaband.W be present age of wife.
H+W=91.
now let diff between their ages be x.that is H-W=x.
now when husband is W yaers old, his wife must be W-x years
old.and it is given that H=2(W-x). so 2W-H=2x. and H-
W=x.eliminating x we get 4W=3H. but H+W=91, so solving thse
two H=52 W=39.

1) time =20mins,speed=15kmph=15*(5/18)=25/6 m/sec
distance=20*(25/6)=250/3 m
then 2) given as time =15min
speed=250/3*15=(50/9)*(18/5)kmph=20kmph

( a ) 10 metres

64

as total 16 floors out of them 11 were rented to A and B company .So remaining floors are 5 and each floor is 12000s.ft
So remaining = 12000*5
=60000

Answer :sister- in- law

explanation: y is the daughter of x’s brothers wife’s father-in-law = y is the daughter of x’s brother’s wife’s father = y is the wife of x’s brother = y is x’s sister-in-law