Ques:- Two trains are on same track and they are coming toward each other. The speed of first train is 50 KMs/h and the speed of second train is 70 KMs/h. A bee starts flying between the trains when the distance between two trains is 100 KMs. The bee first flies from first train to second train. Once it reaches the second train, it flies back to the second train ? and so on until trains collide. Calculate the total distance traveled by the bee. Speed of bee is 40 KMs/h. .
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as total 16 floors out of them 11 were rented to A and B company .So remaining floors are 5 and each floor is 12000s.ft
So remaining = 12000*5
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i will put my sincere effort in my work for upward growth
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A. (125)^15
B. (5)^125
C. (625)^20
D. (25)^10
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125^15 would be 5^18
625^20 would be 5^24
25^10 would yield 5^12
so
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while(true)
{
new Object();
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3, 4, 9, 22.5, 67.5, 202.5, 810
3, 4, 9, 22.5, 67.5, 202.5, 810
A. 4
B. 9
C. 67.5
D. 202.5
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A. 4
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A. 325
B. 1170
C. 1175
D. 2125
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C.1175
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Recent Answer : :
4x:5x:6x
100:50:25
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800x=16000
x = 20
25 paisa=6x = 20×6=120
so the ans is 120 coins
Answer: 66.67 km approx.
Solution:
Let the first train A move at u km/h.
Let the second train B move at v km/h.
Let the distance between two trains be d km
Let the speed of bee be b km/h
Therefore, the time taken by trains to collide = d/(u+v)
Now putting all the known values into the above equation, we get,
u = 50 km/hr
v = 70 km/hr
d = 100 km
b = 80 km/hr
Therfore, the total distance travelled by bee
= b*d/(u+v)
= 80 * 100/(50+70)
= 66.67 km (approx)