Gocompare.com Interview Questions, Process, and Tips

p = prob(1st digit not 7)*prob(2nd digit not 7)*prob(3rd
digit not 7)
=(8/9)*(9/10)*(9/10)
=0.72
Sandhya had it right except that there are 900 numbers
between 100 and 999 inclusive (not 899).

Ans: 60 kph

Suppose Person meets the train everyday at 3 PM at Station A.

His speed is 12kph.

So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.

But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.

Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.

So speed of the train is 5KM/5min = 60 kph.

1.5 hr

Blue

first fill 3quart pail and pour in 5quart pail.fill again 3
quart pail and fill remaining 2 quarts in 5 quart
pail.hence 1 quart remains in 3quart pail.empty 5quart pail
and pour 1 quart from 3 quart pail. also add another 3
quart from 3 quart pail. hence 1 + 3 quarts = 4 quarts.

In 5liter alchol is 20%
In 1liter alchol is0.2÷5=0.04liter

Taken out 2liter solution =3liter solution
Alchol present 3×0.04=0.12liter
7liter water alhol present=0.12liter
12%

600

Had is correct ! Anil went in right direction but ended up
with wrong answers
Soln: B lied ( see anil’s comment ) which implies B has not
stolen mule. So B could steal camel or sheep.
1) Lets assume B stole camel.
In that case, A lies ( refer – A says “B had stolen sheep”
), which implies A had stolen sheep ( becoz a lier cant
steal mule ). So A->sheep B->camel C->mule. But this cant
happen because C cant lie ( refer – C says ” B had stolen
mule” ).
2) Lets assume B stole sheep.
In that case, A is true ( refer – A says “B had stolen
sheep” ), which implies A had stolen mule. So A->Mule
B->Sheep C->camel. Here C lies ( refer – C says ” B had
stolen mule” )
SO ANS: answer A- mule, B-sheep, C camel

A = 20k x 2y, B = 15k x 2y, C = 20k x 1.5y => 100Ky
B contribution = (15k x 2y) /100ky
B will get 0.3 from 25k which is 7.5k = 7500

1.7% loss

NO but i hope to you hire me

12 month=>900Rs+Uniform
1month:75 => 9month:675
675-650=25 =>price of Uniform

Total inversement =20000
Arun and vinay =40% ,40%
Kamal =20%
8 month gain = 4005
Arun and vinay share of 6 months=1201.5
Kamal share of 6 month = 600.75
Now Arun left, then remaining 2 month’s profits =1001.25
In this case kamal have 33.3% and vinay have remaining percentage of 1001.25
33.3% of 1001.25 is 333.4
Now, total share of kamal is 600.75+333.4=934.16

30/100*142.85 = approx. 100
so ans is 42.85