
I value integrity in my work very highly. To me, it means being honest, responsible, and consistent—even when no one is watching. It builds trust with teammates, managers, and clients, and creates a strong foundation for long-term success. I believe doing the right thing, even in small tasks, reflects character and sets the tone for professional growth.
We are given:
1st January 1991 was a Tuesday
We need to find the day of the week on 1st January 1998
Let’s calculate how many odd days (extra days beyond complete weeks) occurred from 1991 to 1997 (because we want the day on 1st Jan 1998).
🗓️ Step 1: Count the years from 1991 to 1997
That’s a total of 7 years
Among them, count how many are leap years.
Leap year condition: divisible by 4
From 1991 to 1997:
1992 ✅ (leap year)
1996 ✅ (leap year)
So:
Leap years = 2 → each gives 2 odd days
Ordinary years = 5 → each gives 1 odd day
Total odd days = (5 × 1) + (2 × 2) = 5 + 4 = 9 odd days
Now, 9 ÷ 7 = 1 week and 2 odd days
🟢 So, 1st January 1998 = 2 days after Tuesday = Thursday
✅ Final Answer:
1st January, 1998 was a Thursday.