Etisalat Software Solutions Interview Questions, Process, and Tips

ans is C.
let H be present age of husaband.W be present age of wife.
H+W=91.
now let diff between their ages be x.that is H-W=x.
now when husband is W yaers old, his wife must be W-x years
old.and it is given that H=2(W-x). so 2W-H=2x. and H-
W=x.eliminating x we get 4W=3H. but H+W=91, so solving thse
two H=52 W=39.

Total inversement =20000
Arun and vinay =40% ,40%
Kamal =20%
8 month gain = 4005
Arun and vinay share of 6 months=1201.5
Kamal share of 6 month = 600.75
Now Arun left, then remaining 2 month’s profits =1001.25
In this case kamal have 33.3% and vinay have remaining percentage of 1001.25
33.3% of 1001.25 is 333.4
Now, total share of kamal is 600.75+333.4=934.16

Chi-ca-go

time = distance / speed
speed = 36*(5/18) m/s=10m/s
distance = 100m
time=100/10s = 10sec

126
cos if one of the factor is given for hcf and lcm and multiply hcf and lcm and them divide it by the given factor
so 18*3780/540=18*7=126

4 years

12

When A runs 1000 meters, B runs 900 meters and when B runs 800 meters, C runs 700 meters.

Therefore, when B runs 900 meters, the distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 meters.

So, in a race of 1000 meters, A beats C by (1000 – 787.5) = 212.5 meters to C.

So, in a race of 600 meters, the number of meters by Which A beats C = (600 x 212.5)/1000 = 127.5 meters.

Ratio: 3/4