Cosmetics store Interview Questions, Process, and Tips

P+C+M=80
P+C=70
Therefore M=10
Given , P+M=90
If M=10
P=80

7 months

these r all factors of 30
1*30=30
2*15=30
3*10=30
5*6=30
like that

The Answer is c

21

125^15 would be 5^18
625^20 would be 5^24
25^10 would yield 5^12
so
The answer is b) i.e. 5^125

4

1) time =20mins,speed=15kmph=15*(5/18)=25/6 m/sec
distance=20*(25/6)=250/3 m
then 2) given as time =15min
speed=250/3*15=(50/9)*(18/5)kmph=20kmph

Let Suvarna, Tara, Uma and Vibha be S,T,U,V respectively
initially in the beginning each persons share be
V = x U = y T = z
S = w = (x+y+z+32) Reason: She has to double others share, so she should have each and everyone’s share and still should be left out with 32

after 1st Round of game
S loses and is out with 32 and doubles the others share
V = 2x U = 2y T = 2z

After 2nd Round of game
T loses and is out with 32 and doubles the others share
V = 4x U = 4y
This means T had 2z = 2x + 2y + 32
After 3rd round of game
U looses and is out with 32 and doubles others share
V = 8x
This means U initially has 4y = 4x + 32
In the end V = 8x = 32

Solving this we get x = 4, y = 12, z = 32 and w = 80
There fore Suvarna had highest share in the beginning

Let:
1. speed of boat in still water = x
2. speed of stream = y;

Then net speed of boat upstream = x – y = 16km / 4 h = 4kmph
Net speed of boat downstream = x + y = 16 / 2 = 8kmph

Now solve for x to get x = 6kmph in still water.

10 a.m.

Fathers before age=3*before sons age—-(1)
After 2.5 years..
Fathers before age+2.5 years =2.5*sons age—-(2)
Substitute (1) in (2),
3*sons before age+2.5 years=2.5*sons age
0.5*sons age=2.5 years
Sons before age=5years
So current age after 2.5 years,
Sons before age+2.5 =5+2.5=7.5 years

1%=50
12%=600