Coimbatore institute of technology Interview Questions, Process, and Tips

324:400:576?
18×18:20×20:24×24:26×26
324:400:576:676

Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45

let t = total no of students.. then
students who passed one or both subjects,
n(e U h) = n(e) + n(h) – n(e intersection h)
=> t = 0.8t + 0.7t – 144
=> t = 1.5t – 144
students who failed both subjects is 10% i.e. 0.1t
=>t-n(e U h) = 0.1t,
=>t -(1.5t – 144) = 0.1t
=>t- 1.5t- 0.1t = -144
=> -0.6t = -144
=>t = 240

zero – as one letter cant be wrong – atleast two are to be wrong

1.5 km/hour

17.9

The work done by A in 8 days is = 8/ 12 = 2/3

Means A alone completes 2/3 part of work.

Remaining work which is (1–2/3) = 1/3 is completed by B in 8–2 = 6 days

So the complete work done by B in 6/(1/3) = 18 days.

B alone can complete the work in 18 days.

X = 4

In 30 mins- Thief – 20km, Owner – 0km
In 1hr – Thief – 40km, Owner – 25km
In 1.5hrs – Thief – 60km, Owner – 50km
In 2hrs – Thief – 80km, Owner – 75km
In 2.5hrs – Thief – 100km, Owner – 100km

Answer: In 2.5 hours the owner would have overtaken the Theif

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