Cheongna dalton school Interview Questions, Process, and Tips

24 Kmp/h

if A is true B has to be true

If n = no. of revolutions for back wheel
9n = 7n + 10*7
n=315

5*2=10
10*5=50
50*10=500
500*50=25000
So odd one is 5000

1440 * 3/4 = 1080
1080 / 30 = 36
1440 * 1/4 = 360
360 / 24 = 15
36 * 2 + 15 * 1 = 87

friendly environment, supportive colleagues and place where i’ll have to work.

area is given by Area of Rectangle = Length of Rectangle*(sqrt((Diagonal of Rectangle^2)-(Length of Rectangle^2)))
so substituting we get area=4*(sqrt((25-16)))
area=4*(sqrt(9))
since area cannot be negative hence we take sqrt of 9 as 3 (as sqrt of 9 is 3 and -3 as well)
area=4*3=12m^2

877.4

This is a sequence of English letters, in numbers.

⇒ ten = 3 letters

⇒ nine = 4 letters

⇒ sixty = 5 letters

⇒ ninety = 6 letters

⇒ seventy = 7 letters

⇒ Sixty six =8 letters

⭕️This logical question goes with the no. of letters in the number!!!!!!!

⭕️∴ the biggest number with 9 letters will be ninety-six (96).

20&130

if am standing on a ballconi so i see the people what they
are doing and how they are handling with the people and
what they are taking to each and everybody.

2.88

First write equations from info:
(A) (Mon + Tue + Wed)/3 = 111 Rearrange as ——–> Tue + Wed = 111 – Mon
(B) (Tue + Wed + Thu)/3 =102 Rearrange as ——–> Tue + Wed = 102 – Thu
(C) Thu = 0.8(Mon)

Substitute equation C into B:
(B) Tue + Wed = 102 – 0.8(Mon)

At this point I changed the values for clearer algebra:
Mon = x
Tue + Wed = y

Re-write equations A & B with new values:
(A) y = 111 – x
(B) y = 102 – 0.8x

Solve simultaneous equations:

111 – x = 102 – 0.8x
111 – 102 = x – 0.8x (Re-arraged)
9 = 0.2x
x = 45

Thus, Mon = 45C

Thu = 0.8(45)
Thu = 36C

So the answer is it was 36C on Thursday

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