Cee Interview Questions, Process, and Tips

Suppose that total 100 employees are in company….. out of that 35 are man and remaining 65 are women.
20% of man 35 = 20*35/100
40% of women = 40*65/100
total employees = 7+26 = 33 out of 100
so, Ans = 33 %

Let the distance between each pole be x m. Then, distance up to 12th pole = 11x m

∴ Speed = 11x22m/s

∴ Time to cover total distance up to 20th pole

= 19x×2411x

= 41.45 s

previous ans wrong again..!!!!
first find x its 2 hours
total journey 6 hrs 3km up and also down
jill takes one hr to come down and jack takes 3 hrs so x
is 2 hours….
And while going up jack goes at 1.5km/hr and jill goes at
0.75 km hr so to travel 3 km they take 2 hrs and 4 hrs
respectively…!!! x again is 2 hrs…
so jack totally takes 5 hrs to travel 6 km
therfore speed is 6/5 km per hour
thats is 1.2 km per hour is the correct answer

Here is the ans with explanation…..
Just divide 48 hours into 8 parts…
for flowchart its 1/4 so it is 2/8 = 12hours
For Coding it is 3/8 = 18 hours
the rest is again 3/8 = 18 hours for debugging..

I think speed of printing per minute has nothing do to with how long printer being at work.

If “given day” = 8 hours.
8h = 480m

x = 176400 / 480 = 367.5 lines per minute.

Let x be fathers present age and y be son present age.
5 yrs ago, the age of father and son be x-5 & y-5.
Then,
x-5+y-5=40
x+y-10=40
x+y=50
y=50-x ———–> (1)
ratio between father and son in present age
x:y=4:1
x/y=4/1
x=4y
Apply eq (1) ,
x=4(50-x)
x=200-4x
x+4x=200
5x=200
x=200/5
x=40,,
=> The present age of father is 40.

890.488

1) time =20mins,speed=15kmph=15*(5/18)=25/6 m/sec
distance=20*(25/6)=250/3 m
then 2) given as time =15min
speed=250/3*15=(50/9)*(18/5)kmph=20kmph

127.179(app)
given distance of the train along the wind is 695
and againt the wind is 498
and time = distance/speed
as we know that time is equal in both the cases hence equate
695/s1=498/s2———–(1);
where s1=speed of the plane + speed of the wind
and s2=speed of the plane -speed of the wind
given that speed of the wind is 21k/h
s1=sp+21
s2=sp-21
substitu in eq 1
we get the answer as 27.17(app)

Divide 30*60 seconds by LCM of Numbers =15

(x+2)^2 -x^2 = 84
X=20
So (20,22)
Sum= 42

12%