Ques:- A bus started from the bus stand at 8 Am and after staying 30 minutes at a destination return back to the bus stand. The Destination is 27 miles from the bus stand . The Speed of the bus is 18mph . In the return journey the bus travells with 50% fast speed.At what time it is return to the bus stand ?
Recent Answer : Added by Admin On 2020-05-17 12:00:34:
Bus started at 8:00
it travelled with 18mph…
distance of destination is 27 miles…
we know velocity=(distance)/time
i.e., time=27/18hours=3/2hours=90 min…
i.e., the bus reached destination at 9:30
the bus stayed for 30 min…
so the bus started return journey at 10:00
now the bus returned with velocity 18 + (18/2)=27mph
the taken to the bus to travel = 27/27=1 hour = 60 min…
so bus would be returned on 11:00…
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A. 918
B. 308
C. 283
D. 279
Recent Answer : Added by narendra On 2022-09-18 09:03:28:
b
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A. 1
B. 2
C. 3
D. 4
Recent Answer : Added by Sneka A On 2022-08-14 16:35:53:
C)3
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Recent Answer : Added by Admin On 2022-09-29 18:55:02:
I solve it as the 280m train being stationary… and the 120m train moving at (42+30) = 72kph…. or 20mps
The front of the train will have to go 280m to pass the stationary train plus another 120m for the backs to clear… that is 400m in all.
The time to travel 400m at 20mps is 20secs
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Recent Answer : Added by Admin On 2020-05-17 12:02:12:
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Recent Answer : Added by narmada On 2022-08-24 17:02:48:
answer is 100
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A. TSULFA
B. AFLUST
C. LUAFST
D. UAFSTL
E. None of these
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Recent Answer : Added by nani Reddy On 2021-08-05 17:11:29:
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Bus started at 8:00
it travelled with 18mph…
distance of destination is 27 miles…
we know velocity=(distance)/time
i.e., time=27/18hours=3/2hours=90 min…
i.e., the bus reached destination at 9:30
the bus stayed for 30 min…
so the bus started return journey at 10:00
now the bus returned with velocity 18 + (18/2)=27mph
the taken to the bus to travel = 27/27=1 hour = 60 min…
so bus would be returned on 11:00…