Brasseler usa Interview Questions, Process, and Tips

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NabasishGogoi

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0L -> 1 way
1L -> 3 ways
2L -> 7 ways
3L -> 4 ways
4L -> 1 way
total 16 ways

d=5
g=1
a=4, b=6,c=2,d=5,e=8,f=3,g=1,h=9,i=7

c

6″

X-340 = X x 4 x 8/ 100

100X – 34000 = 32X
68X = 34000
X = 34000/68
X= 500.

If the bell rung when they r started is also counted then it
will be 5 otherwise 4

data inadequate

0.000256

(c) 25%
20*55*65=y*65*75
y=(20*55*65)/(65*75)
y=14.667 =15
y=15
% reduction=(20-15)/20=25%

5x/4

w, l=2w , area of square =8^2 = 64
area of rectangle = l*b
so w*2w = 8*64
w=16
length = 32

At 680Km

( a ) BQDCJCMF
“TERMINAL” split it into the half we get “TERM” “INAL”

Now the first half is decreased by one and the next half is
increased by one, so we get:

“SDQLJOBM” (pls note in the ques we have “SDQIJOBM” where
‘L’ shud have come instead of ‘I’)

so “CREDIBLE” is to “BQDCJCMF”

(p*r*t)/100 = I ………………..(p*3*10)/100 = 840 …..p = 84000/30 = 2800

answer is 28
>2+8=10
>reverse of 28 is 82
>subtract 28 from 82
>82-28=54
the number is 28

let x be lenghth of candles.

thicker one—- in 1 hr 1/6th will go.
thinner one— in 1 hr 1/4th will go.

let he lit for n hrs.

so in n hrs thicker one goes n/6.
and thinner one goes n/4.

so remainini length are x-n/6 and x-n/4.so x-n/6=2(x-n/4)
implie n=3x. if x=1 n=3hrs.

Let the number of one rupee coins in the bag be x.
Number of 50 paise coins in the bag is 93 – x.
Total value of coins
[100x + 50(93 – x)]paise = 5600 paise
=> x = 74

ANS = 74