Ardentisys Interview Questions, Process, and Tips

Answer is 274 .

Let the required term be x.

Pattern :- 1) Find the difference between consecutive terms as :

2 – 1 = 1

4 – 2 = 2

13 – 4 = 9

31 – 13 = 18

112 – 31 = 81

2) Now write the above numbers obtained by differences in series as :

1, 2, 9, 18, 81, y

(Suppose y be next term after 81.)

3) Look the difference series carefully and it follows the below pattern as :

(9 * 2)/1 = 18

(18 * 9)/2 = 81

(81 * 18)/9 = 162 = y (the next term after 81)

Thus the required answer is :

x = 112 + y

x = 112 +162 =274

4:3
A—–>B (first train)
B——>A(second train)
A/B=Srureroot((time to B)/(time to A))

180*2/3 = 60degree

17:3

I think –

1750 / 7 Years = 250
250 * 2% = 5
5 * 7 Years = 35

Because from there i can do more and learned more too

The answer is A)

y1 = 62 Rs/kg
y2 = 72 Rs/kg
y = 64.5 Rs/kg

y2 – y1 = 10 Rs/kg

The distance between the y and y1 is

y – y1 = 64.5 – 62 = 2.5

x1 = (y – y1)/(y2 – y1) = 2.5/10 = 0.25
x2 = 1 – x1 = 1 – 0.25 = 0.75

The target price is calculated by the lever method.

x1 * y2 + x2 * y1 = 0.25 * 72 + 0.75 * 62.5 = 64.5

The ratio is of y1 to y2 is

0.75 : 0.25

Divide by both by 0.25

3 : 1

240 m

63:45:55

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43.69
Because the total distance will be =100+80000m=80100m. Thus two train coming towards, so the speed will be increase. speed will be =60+50=110km/h, The time of crossing will be 43.69 minutes.

Sachin is 14 years old whereas Rahu is 18 years old.

Relative velocity of trains = 49kmph -25 kmph = 24kmph
=6.67m/s
Time taken to cross the first train = 10 sec
Length of the second train = Relative Velocity * Time taken
to cross the first Train = 6.67 *10 = 66.7 metres