Aisec Interview Questions, Process, and Tips

1.5 hrs

underroot(1-r^2)/3

First write equations from info:
(A) (Mon + Tue + Wed)/3 = 111 Rearrange as ——–> Tue + Wed = 111 – Mon
(B) (Tue + Wed + Thu)/3 =102 Rearrange as ——–> Tue + Wed = 102 – Thu
(C) Thu = 0.8(Mon)

Substitute equation C into B:
(B) Tue + Wed = 102 – 0.8(Mon)

At this point I changed the values for clearer algebra:
Mon = x
Tue + Wed = y

Re-write equations A & B with new values:
(A) y = 111 – x
(B) y = 102 – 0.8x

Solve simultaneous equations:

111 – x = 102 – 0.8x
111 – 102 = x – 0.8x (Re-arraged)
9 = 0.2x
x = 45

Thus, Mon = 45C

Thu = 0.8(45)
Thu = 36C

So the answer is it was 36C on Thursday

A parabola is a conic section.
So cut a cone obliquely.

C. 20

e. 56 is 7*8 which is the product of 7 with even no.

say the work is w and let no of days taken by b is ‘x’ which
we have to calculate
so work done by a in one day is w/6
work done by b in one day is w/x
a and b together can do work in 4 days ie=(w/6)+(w/x)=(w/4)
solving equation x=12
so no of days taken by b=12

Cooking

17and+-12=5-48=-43

let the amount of money be x

cloths 1/3 X x=rs.x/3

balance = x- x/3 = 2x/3

food = 1/5 X 2x/3 = 2x/15

balance = 2x/3 – 2x/15= 8x/15

travel = 1/4 X 8x/15 = 2x/15

now he has 100 rupees

2x/5 = 100
2x= 500
x = 500/2
x = 250

temp at 3.oo pm is = 22.5
temp at 6.oo pm is = 30
thus, percentage rise= 7.5/30 *100
=25%

430
5x5x6 = 150 cube

150 – 20( corner cube) = 130 cube

130 x 3 (side remaining) = 390
20 x 2 (side remaining) = 40
total side remaining = 390 + 40 = 430