Adaptive Financial Consulting Interview Questions, Process, and Tips

Each PAIR of stations means a PAIR of tickets (A to B and B to A)

2(old stations)(new stations) + 2(new stations)(new stations – 1) = 46

(N * X) + (X * (X – 1)) = 23

factoring ___ X (N + X – 1) = 23

23 is a prime number with only two factors, 1 and 23

so N = 23 and X = 1

20/- per day
So, if he work one day
So,1*20=20
1/3*20=20/3
2/3*20=40/3
1/8*20=5/2
3/4*20=15
so,
20+20/3+40/3+5/2+15=57.5
So ans is 57.5 is the ans

A rude person who doesn’t respect me

A=P+SI——(1)
sum of money after 30 years = Double the money
A=2P———-(2)

Equate 1 and 2
P+SI=2P
SI=2P-P
SI=P————-(3)

WKT, SI= PTR/100

Equate 3 and SI

P=PTR/100
P=P*30*R/100
R=P*100/P*30
R=100/30 or 10/3 or 3(1/3) %

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Lipimishra2

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Let the no. of men (originally) be x.
x no. of men require 10 days.

if however there were 10 men less it will take 10 days more for the work to be finished. ——> means x-10 men require 10+10=20 days.

10x = 20 (x-10)
x = 2x -20 => x = 20.

121

17

The Answer is c

Paternal Grandmother

Answer 33
Adding 7,9.13,15,17
Correct is 35

suppose
pipe:
A -30 hours A’s effeciency (60/30) =2
60( lcm of 30 and 20)
B- 20 hours B’s effeciency (60/20)=3

time taken by both to fill = 60/5 =12 as given in question (effeciencies of both a+b =2+3=5)
time taken by faster pipe i.e b = 60/3 =20

Let the firt number be n,
The largest number will be n+1
Their sum
n+n+1=55
2n+1=55
2n=54
n=27
Largest number =27+1=28

₹1 today increases to (1+1/8) = 9/8 after 1year.

After 2 years it increases to 9/8 of 9/8 = (9/8)^2 =81/64 times.

Hence ₹64000 increase to 64000×81/64 =₹81000