AccuraCap Interview Questions, Process, and Tips

1.5 hr

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yea may be they are brothers only by father or by mother

One day’s work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.

C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.

Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.

Remaining Work = 7/10, which was done by A,B and C in the initial number of days.

Number of days required for this initial work = 7 days.

Thus, the total numbers of days required = 4 + 7 = 11 days.

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The correct Answer is 69

21

x (A to B by car) + y (B to A by cycle) is 7 hours

x (A to B by car) + x (B to A by car) is 7 minus 3 is 4 hours

2x is 4 and hence x is 2

2 + y is 7 and hence y is 5

y (A to B by cycle) + y (B to A by cycle) is 5 + 5 is 10 hours

NO but i hope to you hire me

when know that 13 is factor of 39 so it will also not be able to divide it differently. so the remainder will be same 20 but as we know that 20 is greater then 13 so we can divide it once again and in the casE of 13 the remainder will be 20-13=7