Accell group Interview Questions, Process, and Tips

28th February,1956

A certain sum amounts to Rs. 1725 in 3 years

and amounts to Rs.1875 in 5 years

so interest of 2 years = 1875 -1725

= 150

so interest of 1 year = 75

so interest of 3 years = 75 × 3 =225 rs

so , Principal = Amount – SI

= 1725 – 225

= 1500 rs

now ,

S.I. = P × N × R /100

75 = 1500 × 1 × R /100

R = 75 / 15

R = 5%

17:3

First write equations from info:
(A) (Mon + Tue + Wed)/3 = 111 Rearrange as ——–> Tue + Wed = 111 – Mon
(B) (Tue + Wed + Thu)/3 =102 Rearrange as ——–> Tue + Wed = 102 – Thu
(C) Thu = 0.8(Mon)

Substitute equation C into B:
(B) Tue + Wed = 102 – 0.8(Mon)

At this point I changed the values for clearer algebra:
Mon = x
Tue + Wed = y

Re-write equations A & B with new values:
(A) y = 111 – x
(B) y = 102 – 0.8x

Solve simultaneous equations:

111 – x = 102 – 0.8x
111 – 102 = x – 0.8x (Re-arraged)
9 = 0.2x
x = 45

Thus, Mon = 45C

Thu = 0.8(45)
Thu = 36C

So the answer is it was 36C on Thursday

Answer: C

Explanation:

900 — 100
100 — ? => 100/900*100 => 11.11%

50 each
3x -y = 100
4x-2y = 100

200

How breadth is 19.84..?
Apply Pythagoras therom,
a^2+b^2=c^2,
Lets Assume
c is hypotenuse or diagonal,
a is length or opposite side,
b is breadth or adjacent side,
Then,
256+b^2=400
b^2=144
b=12,
So the breadth is 12 cm

Phillips