911 restoration - water, fire and mold damage restoration Interview Questions, Process, and Tips

1600 years contain 0 odd day.
300 years contain 1 odd day.
94 years = (23 leap years + 71 ordinary years)
= (46 + 71) odd days
= 117 odd days, i.e., 5 odd days
Days from 1st January 1995 to 28th February 1995
= (31 + 28) days = 59 days
= (8 weeks + 3 days) = 3 odd days
∴ Total number of odd days
= (0 + 1 + 5 + 3) = 9 odd days i.e., 2 odd days.
So, the required day is Tuesday.

5

350m

Lets call the 5 litre jug as jug A and 3 litre jug as jug B. Now, follow the steps:

Fill jug A completely. Now it contains 5 litres.
Slowly pour the water from jug A to jug B until jug B is completely filled. Now, jug A contains 2 litres and jug B contains 3 litres.
Throw away the water in jug B so that it is completely empty. Now, jug A contains 2 litres and jug B is empty.
Transfer the water from jug A to jug B. Now, jug A is empty and jug B contains 2 litres.
Fill jug A completely. Now, jug A contains 5 litres and jug B contains 2 litres.
Transfer water from jug A to jug B until jug B is completely filled. Now, jug A contains 4 litres and jug B contains 3 litres.

Now you have 4 litres of water in jug A.

data inadequate

11 14
12 15
13 16
=======
14 17
the answers is 14

A & B one day work= 1/18 + 1/30= 8/90

As we know that number of work is 1

1÷8/90= 1*90/8= 90/8.

Since they say “ twice the amount of work

Then ,2*90/8= 22.5 days

16, 28, 36

a/g

divide 100 by 7, and you get 14.28. (Obviously you aren’t talking about decimals here) and so 14 numbers can be divisible by 7 up to 100.

The answer is 14.

23.5 days