Whataburger Interview Questions, Process, and Tips

Let us consider previous salary as a ‘X’ then
0.12*X=0.10*(X+1200)
0.02X=120
X=120/.02=6000
X=6000
His previous salaray was 6000

2/3 * 15 miles = 10 miles then

time for 10 miles travel is t1 = 10/40 = 1/4

then remaning distance is 5 miles

time for 5 miles travel is t2 = 5/60 = 1/12

t1+ t2= 1/3 in seconds * 60 = 20 min

30 Sec

the answer is 3:10
explanation:

let the first number be x
and the second number be y
(7/8)((3/7)x)=(25/100)((45/100)y) given
ie.., 21x/56= 9y/80
on solving we get x:y= 3:10
is the answer

answer is 100
[(45 men*8hours)/30 meters]=12 (working rate)
[(x men*5 hours)/50 meters]=12 (working rate is same)
then x=100

30mins

Let the total time taken to fill the tank be x minutes.

Then, work done by B in half hour + work done by (A+B) in half hour =1.

(
40
1
​
×
2
x
​
)+(
60
1
​
+
40
1
​
)×
2
x
​
=1

⇒
80
x
​
+
48
x
​
=1

⇒
240
3x+5x
​
=1

⇒8x=240

⇒x=30 min

16

20

d / (x+1/2) = 4/5 * t
and d / (x-1/2) = 5/2 + t
solving we get d = 15.

Perimeter of semi circular = πr+2r

Where r is radius , π = 22/7

πr+2r= 144 (given)

(22/7)r +2r = 144

22r+14r = 144*7 (multiply both sides by 7)

36r = 144*7

r= 144*7/36 = 28

radius =28 cm

Area =( 1/2)πr^2

Area=( 1/2 )*(22/7)*28*28

= 1232cm^2
Ans : area is 1232 cm^2

I solve it as the 280m train being stationary… and the 120m train moving at (42+30) = 72kph…. or 20mps

The front of the train will have to go 280m to pass the stationary train plus another 120m for the backs to clear… that is 400m in all.

The time to travel 400m at 20mps is 20secs

1 tank will fill in 10 minutes.

72

72 kmph