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Ques:- A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
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Recent Answer : :
avg sal of 3 is $950
first person earns=$1150
second person earns=$650
let thirdperson =x
avg=(1150+650+x)/3
950*3=1800+x
x=2850-1800
x=$1050
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I think experience because if experience brings pay. If someone having experience in any work then he/she can work easily. Although pay is important but not more then experience
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1, 2, 6, 15, 31, 56, 91
1, 2, 6, 15, 31, 56, 91
A. 15
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C. 56
D. 91
Recent Answer : :
91
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Recent Answer : :
By 1hour both trains meet, so the distance travel by fly in
1hr is 120km.
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1, 1, 2, 6, 24, 96, 720
1, 1, 2, 6, 24, 96, 720
A. 6
B. 24
C. 96
D. 720
Recent Answer : :
C. 96
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Recent Answer : :
C is grand child of A
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( b ) P
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16
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Recent Answer : :
X= pigeon
Y= hares
X+Y= 200
2x+4y=580
By solving y= 90
X=110
So Hares= 90
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Recent Answer : :
0.255555…..
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– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.
– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m
To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec
In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m
at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m
If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)
Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.
For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.
This will take an additional (9.6 + 2) seconds.
Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds