Transcal Interview Questions, Process, and Tips

2.88

we need to take half tabulate among the 4 tablets. den it ll be like 1 tabulate is of fever and one tabulate is of cough

(x-2)^3==x^3-6x^2+12x-8
(x-2)^3==(2^(2/3)+2^(1/3))^3
therefore,by solving
Ans: x^3-6x^2+x== -8-5*2^(2/3)-5*2^(1/3)

Sunil Shetty

b

Length of train = 125Mtrs
Speed of man = 5Km/Hr
=(5*1000)/(1*3600)
=1.4M/s
Time taken for train to pass = 10s

Spd = D/T
Total Distance (Man distance+ Train Length)
#Distance covered by Man in 10s
D=Spd*T
= (1.4M/s*10s)
= 14Mtrs

#Train length = 125Mtrs

Total D = 14Mtrs + 125Mtrs
= 139Mtrs
Time taken = 10s

Sp = D/t
=139M/10s
=13.9M/s

1)Port
2)Trop

let the speed limit be x.
speed by first rider S1 and 2nd rider be S2.
S1=x+10;
ans S2=x+2*10; and given S2=35.
solving we get x=15mph.

2.5 sec

1000 cu.m

360 times

9 am

option B
TCPEOSPR

Ramji sir

Answer: Option D

Explanation:

As Bob is sitting between Charles and Elena and Douglas is sitting to the left of Elena. We get the following arrangement.

Andy is opposite Bob. Therefore, the final arrangement is as follows.

Fred will be sitting right of Charles if each person interchange his/her place with the person sitting opposite them.

140 cents

FYI