Shivamtech engineering design pvt.ltd. Interview Questions, Process, and Tips

1267

10C3 = 120

No of men employed = N

No of days to finish the work = 9 days

No of men after increase = (N + 10)

No of days to finish the work = 6 days

Equating mandays

9N = (N+10)*6

9N — 6N = 60

3N = 60

N = 20

No of men employed = 20

x

38 years

Let Rajan’s present age be x years. Then, his age at the time of marriage = (x – 8) years.

x = 65(x−8)

⇒5x=6x−48

⇒x=48 years

Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = (x – 18) = 30 years

∴ Rajan’s sister’s present age = (30 + 8) years = 38 years

obvious
e^(i*pi) + 1 = 0

6+3.50= 2.50

length is 30 breadth is 12 and height is 12
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1
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1 .
1 .
1 10 .
1
1 .
1
1
1 30 .
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1
consider right angled triangle
so the distance= square root of (30*30+10*10)

Soldier have to move 0.75 miles to West and then 0.375 miles to South to reach the camp.
How:-
Firstly soldier moving 1 mile to East from camp and then 1/2 miles= 0.50 miles to North .

Then it is moving 1/4 miles =0.25 miles to west
And then 1/8 miles =0.125 miles to South

Now we just have to count the difference and minus the value of camp to East with the value of North to west = 1mile – 0.25miles(1/4) = 0.75 miles

Same case with north and south = 0.50 miles(1/2) – 0.125 miles(1/8) = 0.375 miles

Hence proves to return camp the soldier have to move 0.75 miles to west and 0.375 miles to south

b

48,400