Phe engineering Interview Questions, Process, and Tips

Distance covered by B to meet A=Total distance – Distance covered by A hrs

[using : distance = speed x time]

Putting value of from equation (1),

hrs

Therefore, time at which both A and B will meet is = 7 a.m. + 3 hrs =10 am

Slice the cake

X = 4

Total number of pairs is NC2^{N}C_2NC2​. Number of pairs standing next to each other = N. Therefore, number of pairs in question = NC2^{N}C_2NC2​ – N = 28/2 = 14. If N = 7,
7C2​ – 7 = 21 – 7 = 14….
N =7

Daughter-in-law

9 am

I will keep my dog far away from that allergic employee,for that I chain down my dog didn’t leave dog open to avoid moving the dog here there.

47.5

first 10 odd num are 1,3,5,7,9,11,13,15,17,19
sum=100
avg=100/10
avg of 10 odd num =10

2.01

122

400%

e.g:-

l = 5 b = 2
Area= l*b =10

New after 100% increament
l=10 b = 4
Area = 10*4

speed = 72 Kmph
Speed= 72 * 1000 / (60*60) m/s
speed= 72 * 5 / 18
speed= 20 m/s
time = 30 s
distance = 600 m

Let the number be x.

So x-2 =15/x, or

x^2–2x-15=0, or

(x-5)(x+3)=0

Hence x = 5 or -3.

Check: When x=5, 5–2=3 which is 15/5=3.

When x=-3, -3–2=-5 which is 15/-3=-5.

The number is 5 or -3.