MXC Solutions India Interview Questions, Process, and Tips

FUHAZIBA

just will draw the line first and then draw three concentric circles

6/(2+3)-(2+3)/6
=6/5-5/6
=(36-25)/30
=11/30
ans is 11/30

let present age of ANAND AND BALA BE( A AND B ) RESPECTIVELY

A.T.Q

(A-10) = 1/3[B-10]. ……… – {1}

given

B = A+ 12 PUTTING IN 1

THEREFORE A-10 = 1/3 (A+2) = A+2 = 3A – 30

2A =32

A=16

Let\: the\: total\: price \: be\: Rs. X\: then,

B= 2x/7 & A= \left ( x-2 \right )/7

So, A:B = 5x/7 : 2x/7 = 5 : 2

Let \: B’s \: capital\; be\: Rs.Y\: then\: \left ( 16000\ast 8 \right )/4y= 5/2

=> (16000\ast 8\ast 2)/(4\ast 5) = y

=> y = Rs. 12800

the answer is 34

2*3*5*7*11*13*17*19=9699690

4/52 * 3/51

democrate=1008

Here is the solution to the given version of the puzzle (9 balls, one is heavier, need to identify oddball), where we label the balls A, B, …, I:

1. Weigh ABC versus DEF.

Scenario a: If these (1) balance, then we know the oddball is one of G, H, I.

2. Weigh G versus H.

Scenario a.i: If these (2) balance, the oddball is I.

Scenario a.ii: If these (2) do not balance, the heavier one is the oddball.

Scenario b: If these (1) do not balance, then the oddball is on the heavier side. For simplicity, assume the ABC side is heavier, so the oddball is one of A, B, C.

2. Weigh A versus B.

Scenario b.i: If these (2) balance, the oddball is C.

Scenario b.ii: If these (2) do not balance, the heavier one is the oddball.

answer is maximum of 2.