Kyc consulting Interview Questions, Process, and Tips

Ans: 60 kph

Suppose Person meets the train everyday at 3 PM at Station A.

His speed is 12kph.

So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.

But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.

Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.

So speed of the train is 5KM/5min = 60 kph.

A. Rs. 410

11

Ans is 25

150 m

Article price=200
After 25%increase =250
After 25% decrease =187.5

Conclusion 1 follows

the pool will be half full at the 19th day .so that it doubles on the 20th day and becomes full

let no of boys in group is = x
then total sum = 30 * x
after joining one more boys with a weight of 35 kg the total sum is = 30x + 35
after joining the new student the weight will increase 1 kg
so total sum
30x + 35 = 31(x+1)
x = 4

volume of a sphere is 4/3 * pi * r^3
by drilling a hole 6 inches long the volume of the sphere is
not affected bcos the hole is a 1 dimension quantity..(say a
straight line) n so it does not have any value w.r.t volume…
hence the volume of the sphere does not change..

A = 20k x 2y, B = 15k x 2y, C = 20k x 1.5y => 100Ky
B contribution = (15k x 2y) /100ky
B will get 0.3 from 25k which is 7.5k = 7500

A = B + 2
B = 2 C
A + B + C = 27
C = 27 – A – B
B = 2*27 – 2A – 2B
2A = 2*27 – 3B
-2*A =-2*2 – 2*B
B = 10

10 minutes

One day’s work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.

C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.

Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.

Remaining Work = 7/10, which was done by A,B and C in the initial number of days.

Number of days required for this initial work = 7 days.

Thus, the total numbers of days required = 4 + 7 = 11 days.

E

1 through 24, divisible by 2 in descending order.

That leaves you with:
24, 22, 20, 18, 16, 14, 12, 10, 8, 6, 4, 2

8th place FROM the bottom means your answer will be 16.

Out of 10 persons, 4 are graduates; so, (10 – 4) = 6 are under-graduates.

If there is no restriction, any three can be chosen from the ten in (10C3) = 120 ways.

Now, if all three chosen are under-graduates; it can take place in (6C3) = 20 ways.

Therefore, the probability that there will be no graduate among the three chosen = (20 / 120) = (1 / 6).

Therefore, the probability that there will be at least one graduate among the three chosen = {1 – (1 / 6)} = (5 / 6) = 0.8333.