Ques:- In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class? (1) Data inadequate (2) 20 (3) 25 (4) 30 (5) None of these
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(1/2)*x*y
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Money will give Luxury but not experience
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wake up guys and see modulo % can return only integer value.
So answer will be 1 and all other answers are wrong. You can
run your equation in C code and check the output.
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A. 1 Kg
B. 7 Kg
C. 14 Kg
D. 31 Kg
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31
cos
434-403=31
465-434=31
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answer = 16.5Rs
A=3*9=27Rs
B=7*15=105Rs
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therefore,
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5kg mixture price = 13.2*5=66Rs
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A. 54
B. 57
C. 58
D. 60
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57 and 3
12 x 57 = 684
-8 x 3 = -24
684 – 24 = 660
660/ 60 = 11
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300%
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Recent Answer : :
Answer: Pile II
let no. of boys not participating be x
then the no. of girls not participating = x+5
no. of boys : girls participating = 3:2
given no.of boys participating = 15
therefore, the ratio is now 15:y(say)
then 3:2 = 15 : x
on solving 3/2 =15/y ie.., 3y =30 we get y =10
hence no. of girls participating =10
therefore total no of students paricipating = 15+10=25
total no of students in class =60 given
hence no. of students not participating = 60-25=35
therefore x+(x+5)=35
2x=30
x=15
therfore no of girls not participating =15+5=20
therefore total no of girls in class = no of girls
participating + no of girls not participating
=10+20
=30 is the answer