Jesus college oxford Interview Questions, Process, and Tips

35 km/h = 10 m/s
Speed = Distance/Time

Distance= (100+150)m = 250m
Speed = 10 m/s

Time= 250/10 = 25s

Ans is 10%

Printer price = x;
Computer price = 3x
Total overall price = 20x + 60 x 3x = 200x

Printer percent = (20x/200x ) x 100 = 10%

Initially, potatoes have 99% water by weight ; which means they have 1% solid non-water content.

1% of 100 kg = 1 kg

Now even when they dehydrate,this 1kg solid mass remains constant.

It is given that finally, 98% is water by weight , which implies that 2% is non-water solid.

This means 2% of total weight = 1 kg

Total weight *2/100 = 1 kg

Therefore, total weight finally = 50 kg.

c

= (1 * 5! * 2!) * 3 + ( 2! * 5 ! * 1) * 3 + ( 3! * 5! ) + ( 5! * 3! )

The last person covered 120.71 meters.
It is given that the platoon and the last person moved with
uniform speed. Also, they both moved for the identical
amount of time. Hence, the ratio of the distance they
covered – while person moving forward and backword – are
equal.
Let’s assume that when the last person reached the first
person, the platoon moved X meters forward.
Thus, while moving forward the last person moved (50+X)
meters whereas the platoon moved X meters.
Similarly, while moving back the last person moved [50-(50-
X)] X meters whereas the platoon moved (50-X) meters.
Now, as the ratios are equal,
(50+X)/X = X/(50-X)
(50+X)*(50-X) = X*X
Solving, X=35.355 meters
Thus, total distance covered by the last person
= (50+X) + X
= 2*X + 50
= 2*(35.355) + 50
= 120.71 meters
Note that at first glance, one might think that the total
distance covered by the last person is 100 meters, as he
ran the total lenght of the platoon (50 meters) twice.
TRUE, but that’s the relative distance covered by the last
person i.e. assuming that the platoon is stationary.

Since, there are 10 points on the circle and to draw a chord we need to connect any two points on the circle to make it a straight line, which implies that the number of chords = No of lines connecting any two points out of the 10 points

= 10C2 = 10*9/2 = 45 chords.

b

523