Ques:- A car averages 55 mph for the first 4 hours of a trip and averages 70 mph for each additional hour. The average speed for the entire trip was 60 mph. How many hours long is the trip?
Recent Answer : Added by Ant On 2023-05-31 19:22:54:
55 + 70 = 125
125/14hrs = 60 mph
14 hours
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Ques:- Oranges are bought at 11 for a rupee and an equal number more at 9 a rupee. If these are sold at 10 for a rupee, find the loss or gain percent?
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Ques:- A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:40:
the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;
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Recent Answer : Added by Jay On 2022-08-14 16:45:18:
28 Sec
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Recent Answer : Added by Sammani On 2021-08-15 07:59:00:
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Ques:- If sachin score 76more than ahzar , and azhar and robin scores sum is 94 and azhar scores 76 less than dravid and dravid score 26 more than robin . What was the total score done in match?
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Robin =72
Dravid = 98
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Ques:- Number of zeros in the product of the first 100 numbers?
Recent Answer : Added by Admin On 2022-09-28 19:16:12:
1×2×…100=100!
Number of zeros in product of n numbers =[5n]+[52n]+[53n]+…
Number of zeros in product of 100 numbers =[5100]+[52100]+[53100]
where [.] is greatest integer function
=[20]+[4]+[0.8]=20+4=24
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Recent Answer : Added by Admin On 2020-05-17 11:59:49:
30%
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The answer is A)
y1 = 62 Rs/kg
y2 = 72 Rs/kg
y = 64.5 Rs/kg
y2 – y1 = 10 Rs/kg
The distance between the y and y1 is
y – y1 = 64.5 – 62 = 2.5
x1 = (y – y1)/(y2 – y1) = 2.5/10 = 0.25
x2 = 1 – x1 = 1 – 0.25 = 0.75
The target price is calculated by the lever method.
x1 * y2 + x2 * y1 = 0.25 * 72 + 0.75 * 62.5 = 64.5
The ratio is of y1 to y2 is
0.75 : 0.25
Divide by both by 0.25
3 : 1