CORRECT ANS : B
Number of students behind Aruna in rank = (46 – 12) = 34. So, Arun is 35th from the last
Simple interest Formula:
A=P(1+rt)
Therefore,
815=P(1+3r)
P+3r=815
854=P(1+4r)
P+4r=854
Solve the sums using Elimination method.
P+4r=854
P+3r=815
r=39.
Toget Principal
P+4r=854
P+4*39=854
P=854-117
P=698
total no of 4 wheelers: 40
total no of 2 wheelers: 18
M
M. L
L
First write equations from info:
(A) (Mon + Tue + Wed)/3 = 111 Rearrange as ——–> Tue + Wed = 111 – Mon
(B) (Tue + Wed + Thu)/3 =102 Rearrange as ——–> Tue + Wed = 102 – Thu
(C) Thu = 0.8(Mon)
Substitute equation C into B:
(B) Tue + Wed = 102 – 0.8(Mon)
At this point I changed the values for clearer algebra:
Mon = x
Tue + Wed = y
Re-write equations A & B with new values:
(A) y = 111 – x
(B) y = 102 – 0.8x
Solve simultaneous equations:
111 – x = 102 – 0.8x
111 – 102 = x – 0.8x (Re-arraged)
9 = 0.2x
x = 45
Thus, Mon = 45C
Thu = 0.8(45)
Thu = 36C
So the answer is it was 36C on Thursday
6+8+10+10= 36
6²+8²+10²+12²=344
That will depend heavily on when in the journey the 200 men join.
Total marbles are 15
Blue and yellow are 5
Probability is 5/15
36
Turn on a switch and leave it for some ten minutes. Turn it off, turn a second one on and open the door and go into the room. The glowing bulb corresponds to second switch. The bulb that is hot corresponds to first switch, as it was turned on for ten minutes and have heated up. The cold and not-glowing bulb corresponds to the third switch
A control using ActiveX technologies. An ActiveX control
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Java.
let x be the avg age of each person in the family ten years
back…
so total age=6x
after 10 years i.e,now the total age of the family =6x+60
let grand father age as y
then the average of the family=(6x+60-y)/5
(bcoz grand father has expired and the new born baby has no
age at present)
according to the given question (6x+60-y)/5=x
bcoz x is the avg age bfore 10 years.
while calc the equation according to the presnt age we have
to add 10 to the result….
so the answer is 70
1/24-1/40
(5-3)/120
2/120
1/60
60 minutes