Gea process engineering (india) limited Interview Questions, Process, and Tips

these components can be used to add specialized
functionality, such as animation or pop-up menus, to Web
pages, desktop applications, and software development tools.

The formula to find number of diagonals (D) given total number of vertices or sides (N) is

N * (N – 3)

D = ———–

2

Using the formula, we get
1325 * 2 = N * (N – 3)
N2 – 3N – 2650 = 0

Solving the quadratic equation, we get N = 53 or -50

It is obvious that answer is 53 as number of vertices can not be negative.

Alternatively, you can derive the formula as triange has 0 diagonals, quadrangel has 2, pentagon has 5, hexagon has 9 and so on……

Hence the series is 0, 0, 0, 2, 5, 9, 14, …….. (as diagram with 1,2 or 3 vertices will have 0 diagonals).

Using the series one can arrive to the formula given above.

we need to take half tabulate among the 4 tablets. den it ll be like 1 tabulate is of fever and one tabulate is of cough

Use 3pt. Formula
( (x-x1)/(x2-x1) )=( (y-y1)/(y2-y1) )
We get 150

114

Example 1:
Assign, A=20, B=10, C=5, D=5(Because C is equal to D as
given), E=1.
A/B = 20/10 = 2. So A/B = 2
A/C = 20/5 = 4. So A/C = 4
A/E = 20/1 = 20. So A/E = 20
Therefore “A/E is Greatest”
Example 2:
Assign, A=100, B=50, C=20, D=20(Because C is equal to D as
given), E=10.
A/B = 100/50 = 2. So A/B = 2
A/C = 100/20 = 5. So A/C = 5
A/E = 100/10 = 10. So A/E = 10
Therefore “A/E is Greatest”

9828

trick
(r/10)*(r/10)
(20/10)*(20/10)
4% decrese

This is Expert Verified Answer
22 people found it helpful
author link
Lipimishra2

Expert
568 answers
113.9K people helped

Let the no. of men (originally) be x.
x no. of men require 10 days.

if however there were 10 men less it will take 10 days more for the work to be finished. ——> means x-10 men require 10+10=20 days.

10x = 20 (x-10)
x = 2x -20 => x = 20.

Since the total train length passed the tunnel so the distance would be the length of train added to the tunnel legth
D=150+300=450 mt.
speed = distance/time
speed = 450/(40.5/3600)
speed =40,000 mt/sec

21

39 hrs 15 mins..
note:
he will not be having .45 mins for his lunch on saturday..

2a; 2a+2; 2a+4; 2a+6; 2a+8; 2a+10

t_2 + t_6 = 24 => 2a+2 + 2a + 10 = 24 => a = 3

therefore t_4 = 2(3) + 6 = 12

21