General formula for simple interest is SI=PTR/100
Then P= SI x 100 / TR
Here SI= rs.24, T= 2 years, R = 10%
P= 24 x 100 / 2 x 10 = 120 Rs
Answer : Rs. 120
es, of course, there are a lot of people who start their careers with small things but after a few years, they grow themselves and get into better places. All you have to do is learn the skills of your desired domain while working on the other part and then use that to get a job in your desired place.
For example, consider you are an engineer and worked in a firm where you worked as a sales executive but you want to work as an IT professional in any IT firm then while working as a sales executive you can try to learn some coding languages like C or Java and after getting a good command on that you can apply for a job of developer or any IT professional. The only disadvantage is that your sales experience will have nothing to contribute to your IT job so you’ll be hired and paid as a fresher only.
I hope this helps you.
(1/2)*x*y
10 x 27=270
we consider a round shape cake.then cut in 2 equal parts in cut into center and next you have to cut its side by center then you have to get 8 equal parts in 3 exact cut
the answer is 34
33
C
c
let original radius=100
original surface area lets say it x =4 * (22/7) * 100 *100
new radius=100 + 50% of 100=150
new surface area lets say it y = 4 * (22/7)* 150* 150
increase in surface area=((y-x)/x) * 100
i.e.
((4*(22/7)*150*150 – 4*(22/7)*100 *100) / (4*(22/7)*100*100))*100
=125
so the answer is 125%.
hope this helps you.
Initially, potatoes have 99% water by weight ; which means they have 1% solid non-water content.
1% of 100 kg = 1 kg
Now even when they dehydrate,this 1kg solid mass remains constant.
It is given that finally, 98% is water by weight , which implies that 2% is non-water solid.
This means 2% of total weight = 1 kg
Total weight *2/100 = 1 kg
Therefore, total weight finally = 50 kg.
810
Profit one with 3 & 2 nd 2.4
CASE 1: First we should take six balls divided equally and
then it is placed on the two pans.three on one and three on
other..
if the two pans are balanced then the defective ball is not
in the six..then we should the two and keep them one ball
on each.
CASE2: Again We should take any of the six balls and
divided equally and then it is placed on the two pans.. if
any of the pan weighs less than the other.. We should take
the three balls seperately..Now from that three we should
take any two and placed one on each.. fi both the pan
balances the ball which is left over is the defective.. if
one ball weighes less than the other,while keeping one on
each,then it is the defective one….