Fortrade ltd. Interview Questions, Process, and Tips

22

5x/4

Given:

In a group of 15 students,

7 have studied Latin,

8 have studied Greek,

3 have not studied either.

To find:

The number of students who studied both Latin and Greek.

Solution:

In a group of 15 students, have studied Latin, 8 have studied Greek, 3 have not studied either.

Therefore,

n(A∪B) = 15 – 3

n(A∪B) = 12

7 have studied Latin,

n(A) = 7

8 have studied Greek,

n(B) = 8

n(A∩B) is the number of students who studied both Latin and Greek.

n(A∩B) = n(A) + n(B) – n(A∪B)

n(A∩B) = 7 + 8 – 12

n(A∩B) = 15 – 12

n(A∩B) = 3

The number of students who studied both Latin and Greek is 3

Final answer:

3 of them studied both Latin and Greek.

Thus, the correct answer .3

75/8 days

A.

54

Let the person ate x banana on first day, so below is the equation for five days
X+x+6+x+12+x+18+x+24=100
So, he ate 8 banana first day

on the earth

999,919 = 991 × 1,009

Number of cats= 991
Number of mice killed by each cat=1,009

length is 30 breadth is 12 and height is 12
——————————
1
.——————————
1 .
1 .
1 10 .
1
1 .
1
1
1 30 .
——————————-.
1
consider right angled triangle
so the distance= square root of (30*30+10*10)

Pearl.. Head cut then earl.. tail cut then pear.. Head and tail cut then ear

C. 50

325