Ques:- Which greatest number will divide 3026 and 5053 leaving remainders 11 and 13 respectively?
A. 15
B. 30
C. 40
D. 45
Recent Answer : Added by Vijay Vinod On 2022-09-16 14:52:15:
Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45
Ques:- Manisha ranked sixteenth from the top and twenty ninth from the bottom among those who passed an examination. Six boys did not participate in the competition and five failed in it. How many boys were there in the class ?
Recent Answer : Added by Abi On 2021-07-19 18:31:43:
Total 55
Manisha is a girl name so 54 boys
1 girl
Ques:- P, Q and R have Rs.500 between them, P and R together have Rs.200 and Q and R Rs.350. How much does C have?
Recent Answer : Added by Anmol On 2021-06-15 05:45:54:
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Recent Answer : Added by serdar On 2021-09-25 16:19:53:
Ques:- What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
Recent Answer : Added by Sonali On 2020-11-17 15:27:44:
500
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Recent Answer : Added by prasanta mandal On 2022-09-15 16:36:45:
8:7 ratio
Ques:- If 12 men can reap 120 acres of land in 36 days, how many acres of land can 54 men reap in 54 days?
Recent Answer : Added by Nandini Gupta On 2021-10-22 09:12:36:
810
Ques:- if a car starts from A towards B with some velocity due to some problem in the engine afetr travelling 30 km .if the car goes 4/5 th of its of actual velociteythe car reaches B 45 min later to the actual time.if the car engine fails after travelling 45km the car reaches the destination B 36min late to the actual time ,wat is the initial velocity of car and what is the distance between A and B on km.
Recent Answer : Added by Admin On 2020-05-17 12:04:29:
20&130
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Ques:- There are 9 coins. Out of which one is odd one i.e weight is less or more. How many iterations of weighing are required to find odd coin?
Recent Answer : Added by Anonymous On 2021-10-22 09:13:01:
How will you know the odd is in lighter one or heavier one from only one weighing. It will require 2 weighing to find the odd set and one weighing for odd coin in that set i.e total 3 weighings.
Ques:- The ratio of the present ages of P and Q is 3:4. 5 years ago, the ratio of their ages was 5:7. Find the their present ages?
Recent Answer : Added by Madhu moger On 2022-09-15 16:36:43:
30,40
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Ques:- “A soldier loses his way in a thick jungle. At random he walks from his camp but mathematically in an interesting fashion. First he walks one mile East then half mile to North. Then 1/4 mile to West, then 1/8 mile to South and so on making a loop.. Finally how far he is from his camp and in which direction. ..”
Recent Answer : Added by Harsh Shah On 2021-07-22 15:55:58:
Soldier have to move 0.75 miles to West and then 0.375 miles to South to reach the camp.
How:-
Firstly soldier moving 1 mile to East from camp and then 1/2 miles= 0.50 miles to North .
Then it is moving 1/4 miles =0.25 miles to west
And then 1/8 miles =0.125 miles to South
Now we just have to count the difference and minus the value of camp to East with the value of North to west = 1mile – 0.25miles(1/4) = 0.75 miles
Same case with north and south = 0.50 miles(1/2) – 0.125 miles(1/8) = 0.375 miles
Hence proves to return camp the soldier have to move 0.75 miles to west and 0.375 miles to south
Ques:- There are some pigeons and hares in a zoo. If heads are counted, there are 200. If legs are counted, there are 580. The number of hares in the zoo is?
Recent Answer : Added by Amelia On 2022-08-24 17:03:31:
X= pigeon
Y= hares
X+Y= 200
2x+4y=580
By solving y= 90
X=110
So Hares= 90
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Ques:- Find the smallest number which when divided by 13 and 16 leaves respective remainders of 2 and 5.
Recent Answer : Added by Abhishek Gupta On 2022-08-24 17:03:32:
Let ‘N’ is the smallest number which divided by 13 and 16 leaves respective remainders of 2 and 5.
Required number = (LCM of 13 and 16) – (common difference of divisors and remainders)
= (208) – (11) = 197.
Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45