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Ques:- Two trains are on same track and they are coming toward each other. The speed of first train is 50 KMs/h and the speed of second train is 70 KMs/h. A bee starts flying between the trains when the distance between two trains is 100 KMs. The bee first flies from first train to second train. Once it reaches the second train, it flies back to the second train ? and so on until trains collide. Calculate the total distance traveled by the bee. Speed of bee is 40 KMs/h. .
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Recent Answer : :
0,8x= y
y – 0,7y = 270
y= 270 / 0,3
y=900
0,8x=900
x=1125
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LNTKCHMF
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Recent Answer : :
1/3rd of it
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Second
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length of train = 150 m
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3800
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Ques:- The banker’s gain of a certain sum due 2 years hence at 10% per annum is Rs. 24 the present worth is?
Recent Answer : :
General formula for simple interest is SI=PTR/100
Then P= SI x 100 / TR
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P= 24 x 100 / 2 x 10 = 120 Rs
Answer : Rs. 120
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Ques:- Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is
A. 1 : 3
B. 2 : 3
C. 4 : 3
D. 6 : 7
Recent Answer : :
4:3
A—–>B (first train)
B——>A(second train)
A/B=Srureroot((time to B)/(time to A))
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Answer: 66.67 km approx.
Solution:
Let the first train A move at u km/h.
Let the second train B move at v km/h.
Let the distance between two trains be d km
Let the speed of bee be b km/h
Therefore, the time taken by trains to collide = d/(u+v)
Now putting all the known values into the above equation, we get,
u = 50 km/hr
v = 70 km/hr
d = 100 km
b = 80 km/hr
Therfore, the total distance travelled by bee
= b*d/(u+v)
= 80 * 100/(50+70)
= 66.67 km (approx)