Cvm Interview Questions, Process, and Tips

Let n be the number of days it takes A and B, working together, to finish. And we know B=A+10 and B=3A, so:

3A=A+10

2A=10

A=5

Then B=15

So:

1/A + 1/B=1/n where n is the total amount of days. So:

1/5 + 1/15=1/n

3n+n=15

n=15/4 days

40
simple logic, Check Option Lets father present age = 40 so it full fill all condition like his son age become 10 and after five years it will become 15 and father age is 45 and it full fill second condition that fathers age is thrice as old as the son after 5 years

option B
TCPEOSPR

maternal grand mother

on the earth

6 inch

grand daughter

A parabola is obtained as the intersection of a cone with a
plane

3×8=24=2xt ===> t=12hours

Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1​ cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2​ i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61​,P(B)=61​,P(C)=65​,P(A)=61​,P(B)=65​,P(C)=61​ and P(A)=65​,P(B)=61​,P(C)=61​
Hence the required probability = 61​×61​×65​×6×3=21690​=125​

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Lipimishra2

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Let the no. of men (originally) be x.
x no. of men require 10 days.

if however there were 10 men less it will take 10 days more for the work to be finished. ——> means x-10 men require 10+10=20 days.

10x = 20 (x-10)
x = 2x -20 => x = 20.