Ques:- In a group of 15,7 have studied Latin, 8 have studied Greek, and 3 have not studied either.How many of these studied both Latin and Greek
Recent Answer : Added by Admin On 2022-09-29 16:16:30:
Given:
In a group of 15 students,
7 have studied Latin,
8 have studied Greek,
3 have not studied either.
To find:
The number of students who studied both Latin and Greek.
Solution:
In a group of 15 students, have studied Latin, 8 have studied Greek, 3 have not studied either.
Therefore,
n(A∪B) = 15 – 3
n(A∪B) = 12
7 have studied Latin,
n(A) = 7
8 have studied Greek,
n(B) = 8
n(A∩B) is the number of students who studied both Latin and Greek.
n(A∩B) = n(A) + n(B) – n(A∪B)
n(A∩B) = 7 + 8 – 12
n(A∩B) = 15 – 12
n(A∩B) = 3
The number of students who studied both Latin and Greek is 3
Final answer:
3 of them studied both Latin and Greek.
Thus, the correct answer .3
Ques:- A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream
Recent Answer : Added by Jay On 2022-05-17 09:07:04:
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Recent Answer : Added by Praveena Francis On 2021-12-17 16:08:34:
19
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Recent Answer : Added by Pranita Patnaik On 2022-12-20 12:54:04:
I have been teaching some students for 1 year.
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Ques:- A football team played 60 matches out of which 30% were won by them. If they start winning all the next matches after how many matches will the average winning rate be 50% ?
Recent Answer : Added by Suman On 2021-10-07 15:41:23:
Matches played: 60.
Matches won: 30% of 60 => (60*(30/100)) = 18 matches.
Iterative approach:
On adding 1 to matches played and matches won, on every iteration until the win percentage gets to 50. So
19 / 61 = 0.3114754098360656
20 / 62 = 0.3225806451612903
21 / 63 = 0.3333333333333333
22 / 64 = 0.34375
…
…
…
…
Similarly,
41 / 83 = 0.4939759036144578
42 / 84 = 0.5
So, after 60th match 24 more matches has to be played and won to get 50% average winning rate.
Ques:- Perimeter of the back wheel = 9 feet, front wheel = 7 feet on a certain distance, the front wheel gets 10 revolutions more than the back wheel .What is the distance?
Recent Answer : Added by Admin On 2020-05-17 12:04:03:
Let the revolutins made by bigger wheel is: x
then revolution by smaller wheel will be: x+10
Now, the distance covered by both wheels will be same.
So,
7(x+10)=9x
7x+70=9x
70=2x
35=x
so distance travelled=9*35=315
or 7*45=315
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Recent Answer : Added by Admin On 2020-05-17 12:01:45:
while(true)
{
new Object();
}
Ques:- 1.14 expressed as a percent of 1.9 is
A. 6%
B. 10%
C. 60%
D. 90%
Recent Answer : Added by Varshitha On 2022-06-20 11:28:59:
.
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Ques:- Four couples sit around a circular table in a party. Every husband sits to the right of his wife. P, Q, R and S are husbands and T, U, V and W are wives. Q – U and R – V are two married couples. S does not sit next to V. T sits to the left of P, who sits opposite S. Who sits between P and Q?
Recent Answer : Added by Bunny On 2022-03-11 17:00:37:
(T-P)-(U-Q)-(V-R)-(W-S)
S Opposite is Q
U sits the P and Q
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Ques:- A sum of Rs. 64 is made up of 80 coins which are either 100 paise or 50 paise coins. How many coins are of 50 paise?
A. 22
B. 32
C. 42
D. 52
Recent Answer : Added by Avisikta On 2021-12-09 18:39:36:
Let’s say,
I have x coins of 50 paise and (80-x) coins of 100 paise,so the equation is like this ,
50x + (80-x)*100 = 64*100
x = 32
So ,I have 32 coins of 50 paise
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Recent Answer : Added by Admin On 2020-05-17 11:59:21:
cannot be determined .
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Recent Answer : Added by Abdul On 2022-05-17 08:56:28:
O
Ques:- Find out the wrong number in the series: 190, 166, 145, 128, 112, 100, 91
A. 100
B. 112
C. 128
D. 166
Recent Answer : Added by trace On 2022-01-16 17:19:50:
128 is incorrect. There is a difference of multiples of 3 in the number pattern, which starts at 24 and reduces by 3 each time. Therefore the correct pattern would read 190, 166, 145, 127, 112, 100, 91.
this would leave the pattern with differences in the pattern 24, 21, 18, 15, 12, 9. The next number in the pattern would be 6 lower than 91. 91 – 6 = 85. Then 85 -3 – 82, followed by 82 – 0 = 82. After this, if -3 were taken the pattern would start to rise so 82 – – 3 = 85.
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Given:
In a group of 15 students,
7 have studied Latin,
8 have studied Greek,
3 have not studied either.
To find:
The number of students who studied both Latin and Greek.
Solution:
In a group of 15 students, have studied Latin, 8 have studied Greek, 3 have not studied either.
Therefore,
n(A∪B) = 15 – 3
n(A∪B) = 12
7 have studied Latin,
n(A) = 7
8 have studied Greek,
n(B) = 8
n(A∩B) is the number of students who studied both Latin and Greek.
n(A∩B) = n(A) + n(B) – n(A∪B)
n(A∩B) = 7 + 8 – 12
n(A∩B) = 15 – 12
n(A∩B) = 3
The number of students who studied both Latin and Greek is 3
Final answer:
3 of them studied both Latin and Greek.
Thus, the correct answer .3