CEM Benchmarking Interview Questions, Process, and Tips

( c ) R or T

A parabola is obtained as the intersection of a cone with a
plane

In the example first we have to find the area of the field

we have given the following values ,

cost of fencing per meter = Rs 1.50

Diameter of circular field = 28

We have to find the area , a = ?

We know that,

Area = 2 π r

= 2 x 22/7 x 14

= 2 x 22 x 2

= 44 x 2

= 88 sq. m

So, area of circle is 88 sq.m

Now just multiply it with 1.50

cost of fencing = 88 x 1.50

= Rs. 132

So, the cost of fencing the circular field is Rs. 132

option B
TCPEOSPR

mother

45

x (A to B by car) + y (B to A by cycle) is 7 hours

x (A to B by car) + x (B to A by car) is 7 minus 3 is 4 hours

2x is 4 and hence x is 2

2 + y is 7 and hence y is 5

y (A to B by cycle) + y (B to A by cycle) is 5 + 5 is 10 hours

9 AND 3

1900

Let\: the\: total\: price \: be\: Rs. X\: then,

B= 2x/7 & A= \left ( x-2 \right )/7

So, A:B = 5x/7 : 2x/7 = 5 : 2

Let \: B’s \: capital\; be\: Rs.Y\: then\: \left ( 16000\ast 8 \right )/4y= 5/2

=> (16000\ast 8\ast 2)/(4\ast 5) = y

=> y = Rs. 12800

Assuming the youngest has X years, so we have
X+(X+3)+(X+6)+(X+9)+(X+12)=50
5X+30=50
5X=20
X=4
The youngest has 4 years

In 5liter alchol is 20%
In 1liter alchol is0.2÷5=0.04liter

Taken out 2liter solution =3liter solution
Alchol present 3×0.04=0.12liter
7liter water alhol present=0.12liter
12%